AP Guides/AP Chemistry

Free Study Guide · 2026 Exam Season

AP Chemistry Study Guide

Complete AP Chemistry study guide for 2026. Covers all 9 College Board units — acids & bases, equilibrium, thermodynamics, kinetics, and more — with interactive simulations and exam predictions.

Exam complete — preparing for 2027 season
5Units covered
4Interactive elements
100%Free to use
Unit 811–15% of exam

Acids and Bases

The highest-weighted unit on the AP Chemistry exam. Master pH, Ka, buffers, and titrations.

Acids and bases is the single most tested unit on AP Chemistry. Expect 2–4 free-response points and multiple MCQs directly from this unit.

The pH Scale

pH=log[H+]pOH=log[OH]pH+pOH=14\text{pH} = -\log[\text{H}^+] \qquad \text{pOH} = -\log[\text{OH}^-] \qquad \text{pH} + \text{pOH} = 14

At 25°C, a neutral solution has pH = 7. Below 7 is acidic; above 7 is basic.

Strong vs. Weak Acids

Strong acids dissociate 100% in water. The 6 to memorize: HCl, HBr, HI, HNO₃, H₂SO₄, HClO₄.

Weak acids partially dissociate. A larger Ka means a stronger acid. Use an ICE table to find [H⁺] from Ka.

Ka=[H+][A][HA]K_a = \frac{[\text{H}^+][\text{A}^-]}{[\text{HA}]}

ICE Table Example

For 0.10 M acetic acid (Ka = 1.8 × 10⁻⁵):

         CH₃COOH  ⇌  H⁺  +  CH₃COO⁻
Initial:   0.10        0       0
Change:    −x         +x      +x
Equil:   0.10−x       x       x

Ka = x² / (0.10 − x) ≈ x² / 0.10
x = [H⁺] = √(1.8×10⁻⁵ × 0.10) ≈ 1.34×10⁻³ M
pH = −log(1.34×10⁻³) ≈ 2.87

Exam tip: You can drop the '−x' in the denominator when Ka is at least 1000× smaller than the initial concentration (the 5% rule). Always verify: x / [HA]₀ < 5%.

Key Concepts

KaAcid dissociation constant. Larger = stronger acid.
KbBase dissociation constant. Ka × Kb = Kw = 1.0 × 10⁻¹⁴ at 25°C.
BufferA solution of a weak acid and its conjugate base that resists pH change.
Henderson-HasselbalchpH = pKa + log([A⁻]/[HA]) — use for buffer problems.
Equivalence pointPoint in a titration where moles of acid = moles of base.
Acid-Base Solutions Simulator
Interactive · PhET

Acid-Base Solutions Simulator

Drag the concentration slider and switch between strong/weak acids. Watch how pH and particle count change in real time.

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Buffers and Henderson-Hasselbalch

A buffer contains a weak acid (HA) and its conjugate base (A⁻) — typically from a salt. When acid is added, A⁻ absorbs it. When base is added, HA neutralizes it.

pH=pKa+log[A][HA]\text{pH} = \text{p}K_a + \log\frac{[\text{A}^-]}{[\text{HA}]}

Key buffer facts for the exam:

  • Buffer capacity is highest when pH = pKa (equal concentrations of HA and A⁻).
  • Adding a strong acid to a buffer: convert moles, recalculate ratio, plug into H-H.
  • A buffer with high concentrations resists larger pH changes.

Titrations

At the equivalence point of a weak acid–strong base titration, the solution is basic (the conjugate base hydrolyzes). For strong acid–strong base, it's exactly neutral (pH = 7).

The half-equivalence point is where pH = pKa — a great shortcut on FRQs.

Common mistake: Don't confuse the equivalence point with the endpoint. The endpoint is where the indicator changes color — it approximates but isn't always exactly the equivalence point.

Unit 77–9% of exam

Equilibrium

ICE tables, Le Chatelier's principle, Kc, Kp, and solubility equilibria (Ksp).

Chemical equilibrium occurs when the forward and reverse reaction rates are equal. The position of equilibrium is described by the equilibrium constant K.

Writing K Expressions

For the reaction aA + bB ⇌ cC + dD (pure solids and liquids omitted):

Kc=[C]c[D]d[A]a[B]bKp=Kc(RT)Δn,Δn=mol gas productsmol gas reactantsK_c = \frac{[\text{C}]^c[\text{D}]^d}{[\text{A}]^a[\text{B}]^b} \qquad K_p = K_c(RT)^{\Delta n}, \quad \Delta n = \text{mol gas products} - \text{mol gas reactants}

The Reaction Quotient Q

Q has the same form as K but uses current (non-equilibrium) concentrations.

  • Q < K: Reaction shifts right (toward products).
  • Q > K: Reaction shifts left (toward reactants).
  • Q = K: At equilibrium.

Exam tip: Q vs. K is a favorite MCQ topic. Given initial concentrations, calculate Q, compare to K, and state which direction the reaction shifts. Practice this until it's automatic.

States of Matter — Phase Equilibrium
Interactive · PhET

States of Matter — Phase Equilibrium

Heat or cool a substance and watch phase transitions at the molecular level. Observe how temperature shifts the balance between solid, liquid, and gas — a direct visual of Le Chatelier's principle.

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Le Chatelier's Principle

When a system at equilibrium is disturbed, it shifts to partially counteract the change.

DisturbanceShift Direction
Add reactantRight (toward products)
Remove productRight
Increase pressure (gas)Toward fewer moles of gas
Increase temperatureToward endothermic direction
Add inert gas (constant V)No shift

Solubility Equilibria (Ksp)

For a sparingly soluble salt CaF₂ ⇌ Ca²⁺ + 2F⁻:

Ksp=[Ca2+][F]2K_{sp} = [\text{Ca}^{2+}][\text{F}^-]^2

The common-ion effect: adding a common ion decreases solubility. Adding NaF to a CaF₂ solution will make less CaF₂ dissolve.

Key Concepts

KcEquilibrium constant in terms of molar concentrations.
KpEquilibrium constant in terms of partial pressures (for gas reactions).
QReaction quotient — same form as K but with current concentrations.
KspSolubility product constant for a sparingly soluble ionic compound.
Common-ion effectAdding a common ion shifts equilibrium to decrease solubility.

Exam prediction: This topic frequently appears on the AP Chemistry exam. See our full AP Chemistry predictions →

Unit 67–9% of exam

Thermodynamics

Enthalpy, entropy, Gibbs free energy, and predicting spontaneity.

Enthalpy (ΔH)

Enthalpy measures heat flow at constant pressure. Exothermic reactions release heat (ΔH < 0); endothermic reactions absorb heat (ΔH > 0).

Hess's Law: ΔH for a reaction equals the sum of ΔH values for steps that add up to the overall reaction. Flip a reaction → flip the sign of ΔH.

ΔHrxn=ΔHf(products)ΔHf(reactants)\Delta H^\circ_\text{rxn} = \sum \Delta H^\circ_f(\text{products}) - \sum \Delta H^\circ_f(\text{reactants})

Entropy (ΔS)

Entropy measures disorder. Processes that increase entropy (ΔS > 0):

  • Solids → liquids → gases
  • More moles of gas formed than consumed
  • Dissolution of ionic solids (usually)
  • Mixing of substances

Gibbs Free Energy (ΔG)

ΔG=ΔHTΔS\Delta G = \Delta H - T\Delta S

A reaction is spontaneous when ΔG < 0.

ΔHΔSSpontaneous?
− (exo)+ (more disorder)Always
+ (endo)− (less disorder)Never
− (exo)− (less disorder)Low T only
+ (endo)+ (more disorder)High T only

Exam tip: The ΔG = ΔH − TΔS table above is one of the highest-yield things to memorize in all of AP Chemistry. It appears on virtually every exam in some form.

Key Concepts

ΔHEnthalpy change. Negative = exothermic (releases heat).
ΔSEntropy change. Positive = increased disorder.
ΔGGibbs free energy. Negative = spontaneous at that temperature.
Hess's LawΔH for an overall reaction = sum of ΔH for each step.
Standard conditions25°C, 1 atm, 1 M concentrations. Denoted with ° symbol.

Exam prediction: This topic frequently appears on the AP Chemistry exam. See our full AP Chemistry predictions →

Unit 57–9% of exam

Kinetics

Rate laws, reaction mechanisms, the Arrhenius equation, and half-life.

Rate Laws

The rate law expresses how reaction rate depends on concentration. Exponents m and n are determined experimentally — never from stoichiometry. Overall order = m + n.

rate=k[A]m[B]n\text{rate} = k[\text{A}]^m[\text{B}]^n

Integrated Rate Laws

OrderIntegrated Rate LawHalf-Life
0[A] = [A]₀ − ktt½ = [A]₀ / 2k
1ln[A] = ln[A]₀ − ktt½ = 0.693 / k (constant)
21/[A] = 1/[A]₀ + ktt½ = 1 / (k[A]₀)

Arrhenius Equation

Rate constants increase with temperature. Ea is the activation energy; a catalyst lowers Ea without being consumed.

k=AeEa/RTlnk2k1=EaR ⁣(1T11T2)k = Ae^{-E_a/RT} \qquad \ln\frac{k_2}{k_1} = \frac{E_a}{R}\!\left(\frac{1}{T_1} - \frac{1}{T_2}\right)

Gas Properties — Molecular Collisions
Interactive · PhET

Gas Properties — Molecular Collisions

Add heavy/light particles and adjust temperature or volume. Watch how molecular collision frequency changes — the direct cause of reaction rate dependence on temperature and concentration.

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Common mistake: Never read reaction orders from the balanced equation — they must come from experimental data. The coefficients only give orders for elementary steps in a mechanism.

Key Concepts

Rate constant (k)Proportionality constant in the rate law. Units depend on overall reaction order.
Activation energy (Ea)Minimum energy needed for a collision to result in reaction.
Half-life (t½)Time for [reactant] to drop to half its initial value. Only first-order t½ is concentration-independent.
Rate-determining stepThe slowest step in a mechanism. The overall rate law matches this step.
CatalystSpeeds up reaction by lowering Ea. Appears in the mechanism but not the overall equation.
Unit 318–22% of exam

Intermolecular Forces and Properties

The most heavily weighted unit. IMFs determine physical properties — boiling point, viscosity, vapor pressure, and solubility.

Intermolecular forces (IMFs) act between molecules — they are weaker than intramolecular (covalent/ionic) bonds but control physical properties.

Types of IMFs (weakest to strongest)

  1. London Dispersion Forces (LDF) — present in ALL molecules. Caused by temporary dipoles from electron motion. Stronger for larger, heavier, more polarizable molecules.
  2. Dipole-Dipole — between polar molecules (permanent dipoles). Present when molecules have a net dipole moment.
  3. Hydrogen Bonding — special dipole-dipole between H bonded to N, O, or F and a lone pair on another N, O, or F. Much stronger than regular dipole-dipole.
  4. Ion-Dipole — between an ion and a polar molecule. Strongest of the intermolecular forces; important in dissolving ionic compounds in water.

IMFs and Physical Properties

Stronger IMFs → higher boiling point, higher viscosity, lower vapor pressure.

  • Water has an anomalously high boiling point (100°C) for its mass because of extensive hydrogen bonding.
  • Branched molecules have lower boiling points than straight-chain isomers (less surface contact → weaker LDF).
Molecule Polarity Simulator
Interactive · PhET

Molecule Polarity Simulator

Adjust electronegativity values and bond angles to see how molecular geometry determines dipole moment and polarity. Directly connects to predicting IMF type and strength.

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Exam tip: IMF questions often ask you to rank boiling points or explain solubility. Always identify which IMFs are present in each substance before comparing. 'Like dissolves like' — polar solvents dissolve polar/ionic solutes; nonpolar solvents dissolve nonpolar solutes.

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